If it's not what You are looking for type in the equation solver your own equation and let us solve it.
5b^2+25b-5=0
a = 5; b = 25; c = -5;
Δ = b2-4ac
Δ = 252-4·5·(-5)
Δ = 725
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{725}=\sqrt{25*29}=\sqrt{25}*\sqrt{29}=5\sqrt{29}$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-5\sqrt{29}}{2*5}=\frac{-25-5\sqrt{29}}{10} $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+5\sqrt{29}}{2*5}=\frac{-25+5\sqrt{29}}{10} $
| 5b+25b-5=0 | | 9-6x+x^2=x^2-7x+12 | | 18h=12h+35 | | 9-6x+x2=x2-7x+12 | | 75=500(0.05t) | | 250+350=m-14+m | | 10=-4(3x+3)+13 | | x=21/13 | | 8s-1=9s+2 | | 2h-1=0 | | 7x+10-4x+19=90 | | 7x+12(1)=5 | | 3/4x+2/3=7/6x | | 2/3b=15-b | | v=22=-5 | | 3/5+x=2400 | | (x−1)2=−1 | | y=1/2(-12) | | y=1/5(-15)-9 | | -2(x)=2x-9 | | 7x+10+4x+19=180 | | n+(n+2)+(n+4)=555 | | 2/3x+1/4x=7/12 | | 7=3t-5 | | 3x-4+(3x-4)=62 | | 20=1900/r | | (3x+4)/12+(x-10)/12=(x+1)/8 | | (14)(14)c=700 | | 20=x/95 | | 3x+4/12+x-10/12=x+1/8 | | 2y-6+y-6+30=50 | | 6(3-x)=-5(1+x) |